The correct answer to the question is : \(1.392\ Km\)
CALCULATION:
The angle of inclination of the hill with the horizontal ground \(\theta =\ 8^{0}\).
The magnitude of displacement or the distance travelled by the car up that hill is given as -
distance S = 10.0 Km.
We are asked to calculate the vertical displacement.
Applying vector resolution process, we get-
(a) \(Scos\theta\) is the horizontal component
(b) \(Ssin\theta\) is the vertical component.
Hence, the vertical displacement is calculated as -
Vertical displacement \(S_{y} =\ S\sin\theta\)
\(=\ 10\times sin8^{0}\)
= 1.392 Km.
Hence, the vertical displacement of the car is \(1.392\ Km\)
