Using the completing-the-square method, rewrite f(x) = x2 4x − 1 in vertex form.
Af(x) = (x +2)^2 + 1
Bf(x) = (x + 2^)2
Cf(x) = (x + 2^)2 + 4
Df(x) = (x + 2)^2 − 5
Af(x) = (x +2)^2 + 1
Bf(x) = (x + 2^)2
Cf(x) = (x + 2^)2 + 4
Df(x) = (x + 2)^2 − 5