Shadkerlusawebbles
Answered

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds) 5.50 × 10-11 Hz 2.39 × 10-50 Hz 5.45 × 1018 Hz 1.633 × 1027 Hz

Verified Answer :

Energy (E) = Planck's constant (h) * frequency (nu)
\(3.611*10^{-15}J = 6.626 * 10^{-34} * frequency\)
therefore, frequency ~ \(5.45*10^{18}\)

brandonbradford1234

Answer:

Energy (E) = Planck's constant (h) frequency (nu)

3.61110^{-15}J = 6.626 10^{-34} frequency

therefore, frequency ~ 5.45*10^{18}

Explanation:

Related Questions