I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.
1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.
(2xx)+(2x5)+(-3x)+(-35)=(2\(x^{2}\))+(10x)+(-3x)+(-15)=2\(x^{2}\)+7x-15
(2xx)+(2x-5)+(-3x)+(-3-5)=(2\(x^{2}\))+(-10x)+(-3x)+(15)=2\(x^{2}\)-13x+15
Your answer is 2\(x^{2}\)+7x-15 or 2\(x^{2}\)-13x+15. Does that answer your question?
