We know that one container contains \(1 \frac{7}{8}\) and the second container contains \(5 \frac{3}{4}\). To find how many more quarts of water the second container holds than the first one, we do:
\(5 \frac{3}{4} -1 \frac{7}{8}=\) ←Make them have common denominator
\(5 \frac{6}{8}-1 \frac{7}{8=}\) ←Make them into improper fraction
\(\frac{46}{8}- \frac{15}{8}=\) ←Subtract them
\(\frac{31}{8}=\) ←Simplify
\(3 \sqrt[7]{8}\) ←That's your answer
