Answer: 4 moles of \(CO_2\) are produced.
Explanation:
To calculate the number of moles, we use the formula:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)
For butane:
Given mass of butane = 58g
Molar mass of butane = 58 g/mol
Putting values in above equation, we get:
\(\text{Moles of butane}=\frac{58g}{58g/mol}=1mole\)
For the given chemical equation:
\(2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O\)
By Stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide
So, 1 mole of butane will produce = \(\frac{8}{2}\times 1=4moles\) of carbon dioxide
Hence, 4 moles of \(CO_2\) are produced.
