allisonkay7
Answered

A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest.

Find the average angular acceleration of the turntable during the 0.5 s period.

Answer in units of rad/s2

Verified Answer :

Well, the acceleration is the difference of speeds divided by the time period. \(\frac{32.4}{0.5}=64.8rev/s^2\).
One rev/s is \(2\pi rad/s^2\), so our final result is \(64.8*2\pi=407.15rad/s^2\).

bdajel02

Answer:

not sure lol

Explanation:

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