Verified Answer :

\(\frac{a-c}{x-a}=m;\ D:x eq a\\\\m(x-a)=a-c\\\\mx-ma=a-c\\\\mx=a-c+ma\ \ \ \ /:m eq0\\\\x=\frac{a-c+ma}{m}\)

kayt91

\(\frac{a - c}{x - a} = m\)

\((x - a) \frac{a - c}{x - a} = m ( x - a)\)

\(a - c = mx - am\)

\(a - c + am = mx\)

\(\frac{a}{m} - \frac{c}{m} + \frac{am}{m} = x\)

\(\frac{a - c}{m} + a = x\)

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