Verified Answer :

First we need to find delta for function ax2+bx+c = 0
DELTA = b2-4ac
DELTA = 25 -( 415)= 25 - 20 = 5

x1 = (-b-√DELTA)/2a = (-5 - √5)/2
x2 = (-b+√DELTA)/2a (-5+√5)/2
 x1 and x2 are zeros of this function

dr032169

Answer:

C

Step-by-step explanation:

x = (-5 + \(\sqrt{5}\) )/2 , x = (-5 - \(\sqrt{5}\) )/2

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