Verified Answer :

\(6c^2d^{-3}\ \times\ 3c^3d^{-4}=6\cdot3\cdot c^{2+3}d^{-3+(-4)}=18c^5d^{-7}=\frac{18c^5}{d^7}\)


\(\frac{-16p^6q^5}{20q^7}=-\frac{16}{20}p^6q^{5-7}=-\frac{4}{5}p^6q^{-2}=-\frac{4p^5}{5q^2}\)

konrad509

\(6c^2d^{-3}\cdot3c^3d^{-4}=\frac{18c^5}{d^7}\\\\ \frac{-16p^6q^5}{20q^7}=-\frac{4p^6}{5q^2}\)

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