4y-12x+8=0; Solve for y
\(4y-12x+8=0\)\(4y = 12x-8\)\(y = 3x - 2\)
\(4y-12x+8=0\ \ \ \ /+12x\\\\4y+8=12x\ \ \ \ /-8\\\\4y=12x-8\ \ \ \ /:4\\\\y=\frac{12x}{4}-\frac{8}{4}\\\\y=3x-2\)
