Answer:
Magnitude of potential energy is increased by factor "2"
Explanation:
As we know that if two charge particles are placed at some distance "r" from each other then the electrostatic potential energy between two charge particles is given as
\(U = \frac{kq_1q_2}{r}\)
now we know that if the charge of one of the charge particle is increased to twice of initial charge then
\(U' = \frac{kq_1(2q_2)}{r}\)
now we can say from above two equations that
\(U' = 2U\)
so on increase one of the charge to twice of initial value then the potential energy will become TWICE
