Verified Answer :

antonio9990

\(x^2+4x+16=0 \\ \\ \Delta=b^2-4ac \\ \Delta=4^2-4*1*16 \\ \Delta = 16-64 \\ \Delta=-48 \\ \Delta \ \textless \ 0 =\ \textgreater \ \text{we don't have REAL solutions} \\ \\ \text{but it can solve with the multitude of complex numbers }\mathbb{C}\)

Related Questions