how to solve 2^(log(2)3+ log(2)5
\(2^{\log_23+ \log_25 }=\\ 2^{\log_215}=\\ 15\)
\(2^{log_23+log_25}=2^{log_2(3\cdot5)}=2^{log_215}=15\\\\---------------------------\\\\for\ a,b,c\in\mathbb{R^+}\\\\log_ab+log_ac=log_a(b\cdot c)\\\\a^{log_ab}=b\)
