Verified Answer :

Lilith

\(\frac{2}{3x} + \frac{4}{x} = \frac{7}{x+1} \\ \\x eq 0 \ \ and \ \x+1 eq 0 \\ \\x eq 0 \ \ and \ \x eq -1\)

\(\frac{2 }{3x}+\frac{4}{x} = \frac{7}{x+1} \\\\\ \frac{2+12}{3x} = \frac{7}{x+1} \\ \\\frac{14}{3x} = \frac{7}{x+1}\\ \\14(x+1)=3x\cdot 7\)

\(14 x+14=21x \\ \\14=21x-14x \\ \\ 7x=14 \ \ /: 7 \\ \\x=2\)
 

Icuk18sugiarto

\(\frac{2}{3x} + \frac{4}{x} = \frac{7}{x+1}\)

\(\frac{2}{3x} + \frac{12}{3x} = \frac{7}{x+1}\)

\(\frac{14}{3x} = \frac{7}{x+1}\)

\(Cross\ multiply :\)

\(14(x+1) = 7 \times 3x\)

\(14x+14 = 21x\)

\(14x-21x =-14\)

\(-7x =-14\)

\(x = \frac{-14}{-7}\)

\(\boxed{x=2}\)

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