Answer: The required solutions are :
\((a)~n>-\dfrac{120}{p},~~~(b)~h=\dfrac{5m-45}{3}.\)
Step-by-step explanation: We are given to solve the following :
(a) −np − 90 < 30 for n.
We have
\(-np-90<30\\\\\Rightarrow -np<30+90\\\\\Rightarrow -np<120\\\\\Rightarrow n>-\dfrac{120}{p}.\)
(b) 5m − 3h = 45 for h.
We have
\(5m-3h=45\\\\\Rightarrow 3h=5m-45\\\\\Rightarrow h=\dfrac{5m-45}{3}.\)
Thus, the required solutions are :
\((a)~n>-\dfrac{120}{p},~~~(b)~h=\dfrac{5m-45}{3}.\)
