S=2πr2+2πrh; Solve for h.
\(S=2\pi r^2+2\pi rh\)
We need to solve for h. It means we need to get 'h' alone
First we subtract \(2\pi r^2\) on both sides
\(S - 2\pi r^2=2\pi r^2- 2\pi r^2+2\pi rh\)
\(S - 2\pi r^2=2\pi rh\)
Now we divide by \(2\pi r\) on both sides
\(\frac{S - 2\pi r^2}{2\pi r} = \frac{2\pi rh}{2\pi r}\)
\(\frac{S - 2\pi r^2}{2\pi r} =h\)
We got h alone. Solved for h
\(h=\frac{S - 2\pi r^2}{2\pi r}\)