we know that
Area of the square=\(x^{2}\)
where
x is the length side of the square
in this problem
\(x=3^{\frac{2}{7}}\) in
so
\(Area=(3^{\frac{2}{7}})^{2} \\ Area=3^{\frac{(2*2)}{7}} \\ Area=3^{\frac{4}{7}}\)in²
therefore
the answer is the option
three to the power of four sevenths square inches
