How do I do this problem2 - (7/8 - 3/4 =
\(2-(\frac{7}{8} - \frac{3}{4}) = 2-(\frac{7}{8} -\frac{3\times2}{4\times2})=2 - (\frac{7}{8} - \frac{6}{8}) =\\\\2 - (\frac{7-6}{8}) = 2-\frac{1}{8} = \frac{16}{8} - \frac{1}{8} = \frac{15}{8} = \boxed{1\frac{7}{8}}\)
