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shornoramiller3
shornoramiller3 shornoramiller3
  • 15-06-2014
  • Mathematics
Answered

Write the quadratic equation whose roots are 2 and -6, and whose leading coefficient is 1 .(Use the letter  to represent the variable.)  =0

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konrad509
konrad509 konrad509
  • 15-06-2014

\((x-2)(x+6)=\\ x^2+6x-2x-12=\\ x^2+4x-12\)

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Anonymous Anonymous
  • 20-06-2014

\(roots\ are\ 2\ and\ -6\ and\ a=1\ then:\\\\1(x-2)(x+6)=0\\\\x\cdot x+x\cdot6-2\cdot x-2\cdot6=0\\\\x^2+6x-2x-12=0\\\\x^2+4x-12=0\)

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