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For the total population of a large southern city, mean family income is $34,000, with a standard deviation (for the population) of $5,000. Imagine that you are taking subsample of 200 city residents. What is the Z score for $33,000?

Verified Answer :

It will be 43.800 you welcome and that was hard

Answer:

Z= -2.83

Step-by-step explanation:

The formula for calculating z-score is :

\(Z= \frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}} }\)

\(\bar{x}\) = 33000

μ = 34000

n = 200

σ = 5000

Putting all values,

\(Z= \frac{33000-34000}{\frac{5000}{\sqrt{200}} }\)

⇒ Z= -2.83

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