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  • 15-06-2014
  • Mathematics
Answered

Find dy/dx

2x+3y=sinx

Verified Answer :

Anonymous Anonymous
  • 15-06-2014

\(2x+3y=sinx\\\\3y=sinx-2x\ \ \ \ /:3\\\\y=\frac{1}{3}(sinx-2x)\\\\\frac{\delta y}{\delta x}=\left[\frac{1}{3}(sinx-2x)\right]'=\frac{1}{3}\left[(sinx)'-(2x)'\right]=\frac{1}{3}(cosx-2)\)

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