5 consecutive intergers whose sum is 195
x + (x+1) + (x+2) + (x+3) + (x+4) = 1955x + 10 = 1955(x+2) = 195x + 2 = 39x = 37The 5 consecutive integers whose sum is 195 areĀ 37, 38, 39, 40, 41.