6 more than five times a number x is at least 21
To answer this inequation, you have to write the following: 6 + 5x => 21 (we write the 6 more than five times a number x is at least 21)5x => 21 - 6 (transfer the 6)5x => 15 (calculate this)x => 3 (here is the answer)x => 3
5x+6=215×3+6=21if it can be any number more then 21 it could also be5x+6=265×4+6=26
