4b×3b-2b=102 what is b
\(4b\cdot3b-2b=102\\ 12b^2-2b-102=0\\ 6b^2-b-51=0\\ 6b^2+17b-18b-51=0\\ b(6b+17)-3(6b+17)=0\\ (b-3)(6b+17)=0\\\ b=3 \vee b=-\frac{17}{6}\)
4b×3b-2b=10212b^2 - 2b = 10212b^2 - 2b - 102 = 0divide by 26b^2 - b - 51(6b + 17)(b - 3) = 06b + 17 = 06b = -17b = -17/6 or 2 5/6b - 3 = 0b = 3
