solve the equation 4x^2-17x-15=0
\(4x^2-17x-15=0\\ 4x^2-20x+3x-15=0\\ 4x(x-5)+3(x-5)=0\\ (4x+3)(x-5)=0\\ x=-\frac{3}{4} \vee x=5\)
4x^2 - 17x - 15 = 0(4x + 3)(x-5)4x + 3 = 04x = -3x = -3/4x - 5 = 0x = 5