how solve the equation a(n-3)+8=bn solve for n
a(n-3) + 8 = bnan - 3a + 8 = bnan - 3a + 8 = bn-3a + 8 = bn - an-3a + 8 = n(b-a)\(\boxed{n=\frac{-3a + 8}{b-a}}\)