Verified Answer :

\(8 + | 5x - 3 | > 10\\ |5x-3|>2\\ 5x-3>2 \vee 5x-3<-2\\ 5x>5 \vee 5x<1\\ x>1 \vee x<\frac{1}{5}\\ x\in(-\infty,\frac{1}{5})\cup(1,\infty)\)

kayt91

\(8 + |5x - 3| > 10\)

\(|5x - 3| > 2\)

\(|5x| > 5\)

\([x] > 1\)


\(|5x-3| < -2\)

\(|5x| < 1\)

\(|x| < \frac{1}{5}\)


\(1 > x < \frac{1}{5}\)