The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 grams. The velocity of the stone when it reached the target was 15.0 meters/second. What was the value of the kinetic energy of the stone when it reached the target?
1,000 grams = 1 kilogram
20 grams = 0.02 kilogram
Kinetic energy = (1/2) (mass) x (speed)²
(1/2) (0.02) x (15)² =
(0.01) x (225) = 2.25 joules
Answer: 2.25 J
Explanation: Kinetic energy is the energy possessed by an object by virtue of its motion.
\(K.E=\frac{1}{2}\times mv^2\)
m= mass of object= 20 g = 0.02 kg (1 kg= 1000 g)
v= velocity of object= 15 m/s
\(K.E=\frac{1}{2}\times 0.02\times 15^2=2.25kgm^2s^{-2}=2.25J\)
\((1J=1kgm^2s^{-2})\)