Verified Answer :

iloveonedirection

\(2x^2 - x - 6 = 0\)

\((2x - 3) (x + 2) = 0\)

\(2x - 3 = 0\)

\(2x = 3\)

\(x = \frac{3}{2}\)

\(x + 2 = 0\)

\(x = -2\)

\(x = \frac{3}{2} , 2\)

konrad509

\(2x^2-x-6=0\\ 2x^2-4x+3x-6=0\\ 2x(x-2)+3(x-2)=0\\ (2x+3)(x-2)=0\\ x=-\frac{3}{2} \vee x=2\)

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