From the text of the task we can write the equation:
\(3 x^{2} =2(x+4)\\
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3x^2=2x+8\\
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3x^2-2x-8=0\\
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\Delta=(-2)^2-4.3.(-8)=4+96=100\\
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x=\frac{2 \pm\sqrt{100}}{2.3}=\frac{2 \pm10}{6}\\
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x_1=\frac{2-10}{6}=-\frac{8}{6}=-\frac{4}{3}\\
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x_2=\frac{2+10}{2.3}=\frac{12}{6}=2\)
