the perimeter of the triangle shown to the right is 154 meters. find the lenght of each side. (4x)m (7x+2)m (7x+8)m
4x + 7x + 2 + 7x + 8 = 154
18x = 154 - 10
18x = 144
x = 8
Sides: 32 m, 58 m , 64 m
The first to find the length of each side, we have to find the value of x :
\((4x) + (7x + 2) + (7x+8) = 154\)
\(4x + 7x + 7x + 2+8 = 154\)
\(18x +10 = 154\)
\(18x = 154 - 10\)
\(18x = 144\)
\(x = \frac{144}{18}\)
\(\boxed{x=8}\)
Solution First side :
\((4x)m = (4 \cdot 8)m = 32\ m\)
Solution Second Side :
\((7x+2)m = (7(8)+2)m = 58\ m\)
Solution Third Side :
\((7x+8)m = (7(8)+8)m = 64\ m\)