Solve the Equation: √3x-12=0
√3x - 12 = 0
√3x = 12
(√3x)^2 = (12)^2
3x = 144
x = 48
I assume it's \(\sqrt{3x-12}=0\)\(\sqrt{3x-12}=0\\ 3x-12=0\\ 3x=12\\ x=4\)
