Solve for n. 3(n-19)/5=0
When you have a fraction like this, just know that the denominator does not matter. The numerator does because 0/any number = 0.
There are many ways to solve this:
Distribute
\(\frac{3n-57}{5} =0\)
\(\frac{3n-57}{5} *5=0*5\) << the 5/5=1
\(3n-57=0\) << add 57 to both sides
\(3n=57\)
\(\frac{3n}{3} = \frac{57}{3}\) << divide 3 on both sides
57/3=19
OR
Pretend that n-19 = a
\(\frac{3a}{5} =0\)
Multiply 5 on both sides, so you get 3a=0. Then, you divide 3 on both sides.
a=0.
DO NOT FORGET, n-19 = a.
So, n-19=0.
Isolate n by adding 19 to both sides, and
n=19.