5y(2x−3)=y(x+2)+20 where x=3
here x=3so, putting 3 instead of x\(5y(2(3)-3)=y(3+2)+20 \\ 5y(3)=5y+20 \\ 15y-5y=20 \\ 10y=20 \\ y=20/10=2\)
5y(2(3)-3)=y(3+2)+205y(6-3)=y(5)+205y(3)=5y+2015y=5y+2010y=20y=2
