we know that
If the ordered pair is a solution of the equation, then the ordered pair must satisfied the equation
we will proceed to solve each case to determine the solution of the problem
we have
\(y=8x\) -------> equation \(1\)
case a) \((0,8)\)
\(x=0\\y=8\)
For \(x=0\)
substitute the value of x in the equation \(1\) and then compare the values of y
\(y=8*0=0\)
so
\(0
eq 8\)
The ordered pair case a) is not solution
case b) \((-1,8)\)
\(x=-1\\y=8\)
For \(x=-1\)
substitute the value of x in the equation \(1\) and then compare the values of y
\(y=8*(-1)=-8\)
so
\(-8
eq 8\)
The ordered pair case b) is not solution
case c) \((1.5,10)\)
\(x=1.5\\y=10\)
For \(x=1.5\)
substitute the value of x in the equation \(1\) and then compare the values of y
\(y=8*1.5=12\)
so
\(12
eq 10\)
The ordered pair case c) is not solution
case d) \((2,16)\)
\(x=2\\y=16\)
For \(x=2\)
substitute the value of x in the equation \(1\) and then compare the values of y
\(y=8*2=16\)
so
\(16=16\)
The ordered pair case d) is a solution
therefore
the answer is
\((2,16)\)
