List all the factor pairs for 48
we know that
Factor pairs are any two numbers being multiplied to give you a certain number.
\(48\) is a composite number because it has factors other than \(1\) and itself. It is not a prime number. The \(10\) factors of \(48\) are
\(1, 2, 3, 4, 6, 8, 12, 16, 24, and 48\)
The factor pairs of \(48\) are
\(48,1\)------> \(48*1=48\)
\(24,2\)------> \(24*2=48\)
\(16,3\)------> \(16*3=48\)
\(12,4\)------> \(12*4=48\)
\(and\)
\(8,6\)------> \(8*6=48\)
The correct answers are:
\(1, 48;
\\2, 24;
\\3, 16;
\\4, 12;\text{ and }
\\6, 8\)
Explanation:
We can use our divisibility rules to find the factors of 48. First off, we know that 1 is a factor of every number; to make 48 from 1, we multiply 1(48).
Since 48 is even, that means 2 is a factor; 48/2 = 24, so 2 and 24.
For 3, check the sum of the digits. 4+8 = 12; this is divisible by 3, so 48 is divisible by 3. 48/3 = 16, so we have 3 and 16.
For 4, since it is a two digit number, we just have to manually check. 4 goes into 4, and 4 goes into 8, so 4 goes into 48. 48/4 = 12, so we have 4 and 12.
For 5, the number does not end in 5 or 0, so it is not divisible by 5.
For 6, we check for divisibility by 2 and 3. Since it is divisible by both, then it is divisible by 6. 48/6 = 8, so we have 6 and 8.
For 7, since it is such a small number, we can just check. It is not divisible by 7.
We know from earlier that 48 is divisible by 8; 48/6 = 8, so 48/8 = 6. Since we have begun to repeat factors, we are finished.