What is the slope of a trend line that passes through the points (1, 3) and (10, 25)?
using y1-y2 divided by x1-x2, 25-3=22 and 10-1=9 22/9 can be written as a mixed number (2 4/9) kept the same or written as a decimal, (2.4).
Answer:
slope of a trend line that passes through the points (1, 3) and (10, 25) is \(\frac{22}{9}\)
Step-by-step explanation:
Formula of slope(m) for two points is given by:
\(\text{Slope}(m) = \frac{y_2-y_1}{x_2-x_1}\)
Given the two points:
\((1,3)\) and \((10, 25)\)
Substitute these points in the given formula we have;
\(m = \frac{25-3}{10-1}\)
Simplify:
\(m = \frac{22}{9}\)
Therefore, the slope of a trend line that passes through the points (1, 3) and (10, 25) is \(\frac{22}{9}\)