x(x + 3) + 34 = (x + 5)(x + 2)
First, expand to remove parentheses.
\(x^{2} + 3x + 34 = x^{2} + 2x + 5x + 10\)
Second, add '2x + 5x' to get '7x'.
\(x^{2} + 3x + 34 = x^{2} + 7x + 10\)
Third, cancel out '\(x^{2}\)' on both sides.
\(3x + 34 = 7x + 10\)
Fourth, subtract '3x' from both sides.
\(34 = 7x + 10 - 3x\)
Fifth, subtract '7x - 3x' to get '4x'.
\(34 = 4x + 10\)
Sixth, subtract '10' from both sides.
\(34 - 10 = 4x\)
Seventh, subtract '34 - 10' to get '24'.
\(24 = 4x\)
Eighth, divide both sides by '4', leaving the 'x' by itself.
\(\frac{24}{4} =x\)
Ninth, since '24 ÷ 4 = 6', simplify the fraction to '6'.
\(6 = x\)
Tenth, switch your sides to get the answer.
\(x = 6\)
Answer: x = 6
