Answer:
Inverse variation states:
If y varies inversely as x i.,e
\(y \propto \frac{1}{x}\)
then the equation is in the form of:
\(y = \frac{k}{x}\)......[1] , where k is the constant of variation
As per the statement:
y is 1.5 when x is 8
Solve for k:
Substitute the given value in [1] we have;
\(1.5 = \frac{k}{8}\)
Multiply both sides by 8 we have;
12 = k
or
k = 12
Then, the equation become:
\(y = \frac{12}{x}\)
We have to find y when x is 2.
then;
\(y = \frac{12}{2}\)
Simplify:
y = 6
Therefore, the value of y is, 6
