\(\frac{1}{3} h-4( \frac{2}{3} h-3)= \frac{2}{3} h-6\)
First, in the parentheses, combine the numerator (2) and 'h' and also beside it.
\(\frac{1}{3} h-4( \frac{2h}{3} -3)= \frac{2h}{3} -6\)
Second, since 'h' is basically '1', replace the '1' with 'h' to remove it.
\(\frac{h}{3} -4( \frac{2h}{3} -3)= \frac{2h}{3} -6\)
Third, multiply both sides by '3'.
\(h - 12( \frac{2h}{3} -3)=2h - 18\)
Fourth, expand it to remove the parentheses.
\(h - 8h + 36 = 2h - 18\)
Fifth, subtract 'h - 8h' to get '-7h'.
\(-7h + 36 = 2h - 18\)
Sixth, add ' 7h' to both sides.
\(36 = 2h - 18 + 7h\)
Seventh, leave the '7h' and combine '2h + 7h' to get '9h'.
\(36 = 9h - 18\)
Eighth, add '18' to both sides.
\(36 + 18 = 9h\)
Ninth, add '36 + 18' to get '54'.
\(54 = 9h\)
Tenth, divide both sides by '9'.
\(\frac{54}{9} = h\)
Eleventh, since 9 × 6 = 54, simplify the fraction to '6' and flip it around.
\(h = 6\)
Answer: h = 6
