Solve for y.8^3-3y=256^4y
\(8^{3-3y}=256^{4y}\\\\(2^3)^{3-3y}=(2^8)^{4y}\\\\2^{3(3-3y)}=2^{8\cdot4y}\\\\2^{9-9y}=2^{32y}\iff9-9y=32y\\\\-9y-32y=-9\\-41y=-9\ \ \ \ /:(-41)\\\\y=\frac{9}{41}\)