Answer:
201.6 grams is the mass of 6.3 moles of sulfur.
Explanation:
\(Moles(n) =\frac{\text{Mass of the compound}(m)}{\text{molar mass of the compound}(M)}\)
Moles of sulfur ,n= 6.3 moles
Atomic mass of sulfur = M = 32 g/mol
Mass of the sulfur = m = ?
\(m=M\times n\)
\(=6.3 mol\times 32 g/mol=201.6 g\)
201.6 grams is the mass of 6.3 moles of sulfur.
