Verified Answer :

turk3005

\(p > 0 \Rightarrow\)

\(2p+2\) (even)

\(p^3-p\) (odd or even)

\(p^2 + p\) (even)

\(p^2 - p\) (even)

\(7p - 3\) (ODD); 7p odd, 7p-3 = (odd)-(odd)=(odd)

kate200468

\(p>0\\\\(A)\ \ \ 2p+2=2(p+1)\ \rightarrow\ \ even\ number\\\\(B)\ \ \ p^3-p=p(p^2-1)=p(p-1)(p+1)\ \rightarrow\ \ even\ number\\\\(C)\ \ \ p^2+p=p(p+1)\ \rightarrow\ \ even\ number\\\\(D)\ \ \ p^2-p=p(p-1)\ \rightarrow\ \ even\ number\\\\(E)\ \ \ 7p-3=6p-4+p+1=2(3p-2)+p+1\\\\p-odd\ \rightarrow\ \ (p+1)- even\ \rightarrow\ (7p-3)-even\ number\\\\p-even\ \rightarrow\ \ (p+1)- odd\ \rightarrow\ (7p-3)-odd\ number\\\\Ans.\ E\)

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