5(x-3)+2x=41please help me
Use a(b-c) = ab - ac5(x-3) + 2x = 415x - 15 + 2x = 417x - 15 = 417x = 56x = 8
5(x-3)+2x=41Multiply the x and -3 by 5 to get 5x and -155x-15+2x=41then combine like terms 5x+2x to get 7x7x-15=41then add 15 to both sides to get he x alone7x=56then divide by 56 by 7 to get 1xx=8
