janneth98 janneth98

29-05-2014
Mathematics

Answered

3w squared-8w+4=0

(solving quadartc equations by factoring)

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tadvisohil886 tadvisohil886

30-05-2014

\(3w^{2} - 8w + 4 \\ = 3w^{2} - 6w - 2w + 4 \\= 3w(w - 2) -2( w - 2) \\ = (3w - 2)(w - 2) \\ w = 2/3 , w = 2\)

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kate200468 kate200468

30-05-2014

\(3w^2-8w+4=0\\\\3w^2-6w-2w+4=0\\\\3w(w-2)-2(w-2)=0\\\\(w-2)(3w-2)=0\\\\w-2=0\ \ \ or\ \ \ 3w-2=0\\\\w=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ w= \frac{2}{3}\)

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