$\begin{array}{l}

g(x)=\frac{3}{5} x+\frac{7}{6} \\

h(x)=6 x-5

\end{array}$



The functions $g$ and $h$ are defined by the equations shown. Which expression is equivalent to $g(x) \cdot h(x)$?

Verified Answer :

  • Multiply the two linear binomials \(g(x)\) and \(h(x)\) using the distributive property.
  • Calculate each of the four components of the expansion: \(\frac{18}{5}x^2\), \(-3x\), \(7x\), and \(-\frac{35}{6}\).
  • Combine the linear terms \(-3x\) and \(7x\) to get \(4x\).
  • The final equivalent quadratic expression is \(\boxed{\frac{18}{5}x^2 + 4x - \frac{35}{6}}\).

Explanation

  1. Understanding the Problem

We are given two functions defined by the equations \(g(x) = \frac{3}{5}x + \frac{7}{6}\) and \(h(x) = 6x - 5\). The objective is to find the expression equivalent to the product \(g(x) \cdot h(x)\), which is:
\[g(x) \cdot h(x) = \left(\frac{3}{5}x + \frac{7}{6}\right)(6x - 5)\]
This involves multiplying two linear binomials, resulting in a quadratic expression of the form \(Ax^2 + Bx + C\).

  1. Applying the Distributive Property

To calculate the product, we use the distributive property (often called the FOIL method, which stands for First, Outer, Inner, Last):
\[g(x) \cdot h(x) = \left(\frac{3}{5}x \cdot 6x\right) + \left(\frac{3}{5}x \cdot -5\right) + \left(\frac{7}{6} \cdot 6x\right) + \left(\frac{7}{6} \cdot -5\right)\]
We calculate each of these four products individually:

  1. First terms: \(\frac{3}{5}x \cdot 6x = \frac{18}{5}x^2\)
  2. Outer terms: \(\frac{3}{5}x \cdot -5 = -3x\)
  3. Inner terms: \(\frac{7}{6} \cdot 6x = 7x\)
  4. Last terms: \(\frac{7}{6} \cdot -5 = -\frac{35}{6}\)
  1. Combining Like Terms and Final Result

Now we substitute these results back into the expression and combine like terms (the terms containing \(x\)):
\[g(x) \cdot h(x) = \frac{18}{5}x^2 - 3x + 7x - \frac{35}{6}\]
Combining the terms \(-3x\) and \(7x\), we get \(4x\). Thus, the final quadratic expression is:
\[g(x) \cdot h(x) = \frac{18}{5}x^2 + 4x - \frac{35}{6}\]

Examples

In real-world applications like economics or engineering, multiplying functions is a common task. For example, if a company's price per unit \(p(x)\) and demand \(d(x)\) are both expressed as linear functions of the number of units sold \(x\), the revenue \(R(x) = p(x) \cdot d(x)\) becomes a quadratic function. Determining the correct expression for revenue allows businesses to analyze their profit potential and identify the optimal production levels. Here, we used algebraic multiplication to find a model that represents the combined growth of two linear factors.