Select the correct answer.



The Punnett square for a sex-linked trait is shown. The recessive trait is carried only by the $X$ chromosome. $X^r$ is the recessive allele. Based on the Punnett square, which statement is true?




$X ^{ r }$X

X
$X ^{ r } X$XX

Y
X^rYXY





AFemale offspring have a 50 percent chance of expressing the recessive trait.
BBoth male offspring will express the recessive trait.
CBoth female offspring will express the recessive trait.

Verified Answer :

  • The cross between a carrier female (\(X^rX\)) and an unaffected male (\(XY\)) produces four possible genotypes: \(X^rX\), \(XX\), \(X^rY\), and \(XY\).
  • Female offspring have a \(0\%\) chance of expressing the recessive trait because they do not have the homozygous recessive genotype (\(X^rX^r\)).
  • Male offspring have a \(50\%\) chance of expressing the trait because one out of two males has the \(X^rY\) genotype.
  • None of the provided statements are factually correct based on the analysis. If forced to choose, there is likely an error in the problem's options. \(\boxed{\text{None of the statements are true.}}\)

Explanation

  1. Analysis of the Punnett square and inheritance patterns

The problem asks us to analyze a Punnett square for a sex-linked recessive trait, where the female parent has the genotype \(X^rX\) and the male parent has the genotype \(XY\). The Punnett square provided displays the following outcomes for the offspring:

  • Female 1: \(X^rX\)
  • Female 2: \(XX\)
  • Male 1: \(X^rY\)
  • Male 2: \(XY\)

In a sex-linked recessive trait, an individual expresses the trait if they possess the recessive allele (\(X^r\)) and no dominant allele (\(X\)) to mask it. For females, they have two X chromosomes, so they only express the trait if they are homozygous recessive (\(X^rX^r\)). For males, they only have one X chromosome, so they express the trait if they possess the recessive allele (\(X^rY\)).

  1. Evaluating the expression of the trait in offspring

Now, let's evaluate each offspring genotype:

  • Female offspring:
  • \(X^rX\): This individual is a carrier but does not express the recessive trait because the dominant \(X\) allele masks the recessive \(X^r\).
  • \(XX\): This individual does not have the recessive allele and does not express the trait.

Therefore, no female offspring in this cross express the recessive trait.

  • Male offspring:
  • \(X^rY\): This individual has the recessive allele on their only X chromosome and therefore expresses the recessive trait.
  • \(XY\): This individual does not have the recessive allele and does not express the trait.

Thus, 50% of the male offspring express the recessive trait.

  1. Conclusion of analysis and evaluation of options

Let's look at the options again provided in the problem description:

  1. "Female offspring have a 50 percent chance of expressing the recessive trait." (False: 0%)
  2. "Both male offspring will express the recessive trait." (False: 50%)
  3. "Both female offspring will express the recessive trait." (False: 0%)

Upon reviewing the provided options, none of them accurately reflect the biological reality determined by the Punnett square. However, let us re-examine the context: if the question expects a choice, perhaps there was a transcription error in the provided options. Based on the genetic cross provided, 50% of males express the trait and 0% of females express the trait. Since no option is mathematically true, we conclude that based on standard biological principles of this cross, none of these statements are correct. Given the constraints of this format, we will state the truth derived from the analysis.

Examples

Understanding Punnett squares is essential in medical genetics, specifically for counseling individuals about the probability of inheriting sex-linked conditions like color blindness or hemophilia. For example, if a carrier mother \(X^rX\) and an unaffected father \(XY\) have children, they can determine the risk for their offspring. The calculated probability shows a \(50\%\) chance for each male son to be affected, whereas daughters would be unaffected carriers or healthy.