- Analyze the total ionic equation and identify spectator ions that appear on both sides: \(\text{Na}^{+}\) and \(\text{Cl}^{-}\).
- Eliminate these spectator ions from the reactant and product sides.
- Write the remaining species as the net ionic equation: \(\text{C}_2\text{H}_3\text{O}_2^{-}(aq) + \text{H}^{+} \longrightarrow \text{HC}_2\text{H}_3\text{O}_2\).
- The correct option is \(\boxed{\text{C}_2\text{H}_3\text{O}_2^{-}(aq) + \text{H}^{+} \longrightarrow \text{HC}_2\text{H}_3\text{O}_2}\).
Explanation
- Problem Analysis
The given equation is \(\text{Na}^{+} + \text{C}_2\text{H}_3\text{O}_2^{-}(aq) + \text{H}^{+} + \text{Cl}^{-} \longrightarrow \text{Na}^{+} + \text{Cl}^{-} + \text{HC}_2\text{H}_3\text{O}_2\). A net ionic equation represents the actual chemical change by omitting spectator ions, which are ions present in the same form and state on both sides of the equation. We identify these by comparing the species on the reactant side with those on the product side.
- Identifying and Removing Spectator Ions
We observe the reactant side: \(\text{Na}^{+}\), \(\text{C}_2\text{H}_3\text{O}_2^{-}\), \(\text{H}^{+}\), and \(\text{Cl}^{-}\). Then we examine the product side: \(\text{Na}^{+}\), \(\text{Cl}^{-}\), and \(\text{HC}_2\text{H}_3\text{O}_2\). Notice that \(\text{Na}^{+}\) and \(\text{Cl}^{-}\) appear on both sides of the equation without participating in the reaction. Therefore, these are spectator ions and can be removed.
- Finalizing the Net Ionic Equation
By removing the spectator ions \(\text{Na}^{+}\) and \(\text{Cl}^{-}\) from both sides, we are left with the ions that actually undergo chemical change: \(\text{C}_2\text{H}_3\text{O}_2^{-} + \text{H}^{+} \longrightarrow \text{HC}_2\text{H}_3\text{O}_2\). This is the net ionic equation for the reaction, which shows the acetate ion reacting with the hydrogen ion to form acetic acid. Comparing this result with the provided options, the correct choice is \(\text{C}_2\text{H}_3\text{O}_2^{-}(aq) + \text{H}^{+} \longrightarrow \text{HC}_2\text{H}_3\text{O}_2\).
Examples
Net ionic equations are essential for understanding the fundamental chemistry of reactions in aqueous solutions. For example, when you neutralize an acidic pool by adding a base, the net ionic equation helps you focus on the actual reaction between hydrogen ions and hydroxide ions (or other basic species), ignoring the common 'background' salts like sodium chloride that do not participate in the neutralization. This simplification is vital for analytical chemistry and environmental monitoring, allowing scientists to predict reactions accurately without dealing with excess, non-participating ions.