- Identify the given relation \(f(n+1) = f(n) - 3\) as an arithmetic progression with a common difference of \(d = -3\).
- Use the formula for the \(n\)-th term of an arithmetic progression, \(f(n) = f(1) + (n-1)d\).
- Substitute \(n=4\) and \(f(4)=22\) into the formula to create the equation \(22 = f(1) + 3(-3)\).
- Solve the equation to find the first term: \(f(1) = \boxed{31}\).
Explanation
- Analysis of the Sequence
The sequence is defined by the recursive relation \(f(n+1) = f(n) - 3\). This tells us that each term in the sequence is obtained by subtracting 3 from the previous term. Such a sequence is known as an arithmetic progression, where the common difference is \(d = -3\). We are given the fourth term, \(f(4) = 22\), and our goal is to find the first term, \(f(1)\).
- Applying the Arithmetic Sequence Formula
The general term of an arithmetic progression can be expressed using the formula \(f(n) = f(1) + (n - 1)d\), where \(d\) is the common difference. We know that \(f(4) = 22\), \(n = 4\), and \(d = -3\). Substituting these values into the formula, we get:
\[f(4) = f(1) + (4 - 1)(-3)\]
\[22 = f(1) + 3(-3)\]
\[22 = f(1) - 9\]
- Calculating the First Term
To find \(f(1)\), we solve the linear equation derived in the previous step by adding 9 to both sides:
\[f(1) = 22 + 9\]
\[f(1) = 31\]
Alternatively, we can work backward step by step from the known term:
\[f(4) = 22\]
\[f(3) = f(4) + 3 = 22 + 3 = 25\]
\[f(2) = f(3) + 3 = 25 + 3 = 28\]
\[f(1) = f(2) + 3 = 28 + 3 = 31\]
Both approaches consistently show that the first term is 31.
Examples
Arithmetic sequences are frequently used in financial planning, such as calculating the total amount of money in a savings account where a fixed amount is added or withdrawn periodically. For instance, if you start with an initial deposit and withdraw exactly \(\$3\) every month, you can easily project your account balance over time using the same sequence logic. This model is essential for budgeting and understanding linear growth or decline in various real-world processes.